3x^(2/3)+16x^(1/3)+16=0

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Solution for 3x^(2/3)+16x^(1/3)+16=0 equation: 


x in (-oo:+oo)

3*x^(2/3)+16*x^(1/3)+16 = 0

t_1 = x^(1/3)

3*t_1^2+16*t_1^1+16 = 0

3*t_1^2+16*t_1+16 = 0

DELTA = 16^2-(3*4*16)

DELTA = 64

DELTA > 0

t_1 = (64^(1/2)-16)/(2*3) or t_1 = (-64^(1/2)-16)/(2*3)

t_1 = -4/3 or t_1 = -4

t_1 = -4

x^(1/3)+4 = 0

1*x^(1/3) = -4 // : 1

x^(1/3) = -4

( -4 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = -4/3

x^(1/3)+4/3 = 0

1*x^(1/3) = -4/3 // : 1

x^(1/3) = -4/3

( -4/3 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

x belongs to the empty set

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